(20-2x)=16+10x

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Solution for (20-2x)=16+10x equation: 



(20-2x)=16+10x

We move all terms to the left:

(20-2x)-(16+10x)=0

We add all the numbers together, and all the variables

(-2x+20)-(10x+16)=0

We get rid of parentheses

-2x-10x+20-16=0

We add all the numbers together, and all the variables

-12x+4=0

We move all terms containing x to the left, all other terms to the right

-12x=-4

x=-4/-12

x=1/3

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