x*2-(x-2)*2=4*(x+1)-5

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Solution for x*2-(x-2)*2=4*(x+1)-5 equation: 



x*2-(x-2)*2=4(x+1)-5

We move all terms to the left:

x*2-(x-2)*2-(4(x+1)-5)=0

We multiply parentheses

x*2-2x-(4(x+1)-5)+4=0

Wy multiply elements

2x-2x-(4(x+1)-5)+4=0



We calculate terms in parentheses: -(4(x+1)-5), so:

4(x+1)-5

We multiply parentheses

4x+4-5

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

-(4x-1)+4=0

We get rid of parentheses

-4x+1+4=0

We add all the numbers together, and all the variables

-4x+5=0

We move all terms containing x to the left, all other terms to the right

-4x=-5

x=-5/-4

x=1+1/4

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