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(2x+0.4)(2x+0.4)=4x
We move all terms to the left:
(2x+0.4)(2x+0.4)-(4x)=0
We add all the numbers together, and all the variables
-4x+(2x+0.4)(2x+0.4)=0
We multiply parentheses ..
(+4x^2+0.8x+0.8x+0.16)-4x=0
We get rid of parentheses
4x^2+0.8x+0.8x-4x+0.16=0
We add all the numbers together, and all the variables
4x^2-2.4x+0.16=0
a = 4; b = -2.4; c = +0.16;
Δ = b2-4ac
Δ = -2.42-4·4·0.16
Δ = 3.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{3.2}}{2*4}=\frac{2.4-\sqrt{3.2}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{3.2}}{2*4}=\frac{2.4+\sqrt{3.2}}{8} $
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