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x(x+0.2)=0.15
We move all terms to the left:
x(x+0.2)-(0.15)=0
We add all the numbers together, and all the variables
x(x+0.2)-0.15=0
We multiply parentheses
x^2+0.2x-0.15=0
a = 1; b = 0.2; c = -0.15;
Δ = b2-4ac
Δ = 0.22-4·1·(-0.15)
Δ = 0.64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{0.64}}{2*1}=\frac{-0.2-\sqrt{0.64}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{0.64}}{2*1}=\frac{-0.2+\sqrt{0.64}}{2} $
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