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(2x+39)=(x-19)
We move all terms to the left:
(2x+39)-((x-19))=0
We get rid of parentheses
2x-((x-19))+39=0
We calculate terms in parentheses: -((x-19)), so:We get rid of parentheses
(x-19)
We get rid of parentheses
x-19
Back to the equation:
-(x-19)
2x-x+19+39=0
We add all the numbers together, and all the variables
x+58=0
We move all terms containing x to the left, all other terms to the right
x=-58
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