x*(40/1,11)=890

Solution for x*(40/1,11)=890 equation:

x(40/1.11)=890

We move all terms to the left:

x(40/1.11)-(890)=0

We add all the numbers together, and all the variables

x(+40/1.11)-890=0

We multiply parentheses

40x^2-890=0

a = 40; b = 0; c = -890;
Δ = b2-4ac
Δ = 02-4·40·(-890)
Δ = 142400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{142400}=\sqrt{1600*89}=\sqrt{1600}*\sqrt{89}=40\sqrt{89}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{89}}{2*40}=\frac{0-40\sqrt{89}}{80}
=-\frac{40\sqrt{89}}{80}
=-\frac{\sqrt{89}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{89}}{2*40}=\frac{0+40\sqrt{89}}{80}
=\frac{40\sqrt{89}}{80}
=\frac{\sqrt{89}}{2}
$