(3g+12)(11g-23)=0

Solution for (3g+12)(11g-23)=0 equation:

(3g+12)(11g-23)=0

We multiply parentheses ..

(+33g^2-69g+132g-276)=0

We get rid of parentheses

33g^2-69g+132g-276=0

We add all the numbers together, and all the variables

33g^2+63g-276=0

a = 33; b = 63; c = -276;
Δ = b2-4ac
Δ = 632-4·33·(-276)
Δ = 40401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{40401}=201$
$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-201}{2*33}=\frac{-264}{66}
=-4
$
$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+201}{2*33}=\frac{138}{66}
=2+1/11
$