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x(1+1/x)+17=3(2-x)
We move all terms to the left:
x(1+1/x)+17-(3(2-x))=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
x(1/x+1)-(3(-1x+2))+17=0
We multiply parentheses
x^2+x-(3(-1x+2))+17=0
We calculate terms in parentheses: -(3(-1x+2)), so:We get rid of parentheses
3(-1x+2)
We multiply parentheses
-3x+6
Back to the equation:
-(-3x+6)
x^2+x+3x-6+17=0
We add all the numbers together, and all the variables
x^2+4x+11=0
a = 1; b = 4; c = +11;
Δ = b2-4ac
Δ = 42-4·1·11
Δ = -28
Delta is less than zero, so there is no solution for the equation
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