2(2x-3)-2=2(x-2)+8

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Solution for 2(2x-3)-2=2(x-2)+8 equation: 



2(2x-3)-2=2(x-2)+8

We move all terms to the left:

2(2x-3)-2-(2(x-2)+8)=0

We multiply parentheses

4x-(2(x-2)+8)-6-2=0



We calculate terms in parentheses: -(2(x-2)+8), so:

2(x-2)+8

We multiply parentheses

2x-4+8

We add all the numbers together, and all the variables

2x+4

Back to the equation:

-(2x+4)



We add all the numbers together, and all the variables

4x-(2x+4)-8=0

We get rid of parentheses

4x-2x-4-8=0

We add all the numbers together, and all the variables

2x-12=0

We move all terms containing x to the left, all other terms to the right

2x=12

x=12/2

x=6

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