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x(x-6)=68
We move all terms to the left:
x(x-6)-(68)=0
We multiply parentheses
x^2-6x-68=0
a = 1; b = -6; c = -68;
Δ = b2-4ac
Δ = -62-4·1·(-68)
Δ = 308
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{308}=\sqrt{4*77}=\sqrt{4}*\sqrt{77}=2\sqrt{77}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{77}}{2*1}=\frac{6-2\sqrt{77}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{77}}{2*1}=\frac{6+2\sqrt{77}}{2} $
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