7(2r+5)=6(r-7)

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Solution for 7(2r+5)=6(r-7) equation: 



7(2r+5)=6(r-7)

We move all terms to the left:

7(2r+5)-(6(r-7))=0

We multiply parentheses

14r-(6(r-7))+35=0



We calculate terms in parentheses: -(6(r-7)), so:

6(r-7)

We multiply parentheses

6r-42

Back to the equation:

-(6r-42)



We get rid of parentheses

14r-6r+42+35=0

We add all the numbers together, and all the variables

8r+77=0

We move all terms containing r to the left, all other terms to the right

8r=-77

r=-77/8

r=-9+5/8

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