x(x-6)=(x-1)(x+2)-6

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Solution for x(x-6)=(x-1)(x+2)-6 equation: 



x(x-6)=(x-1)(x+2)-6

We move all terms to the left:

x(x-6)-((x-1)(x+2)-6)=0

We multiply parentheses

x^2-6x-((x-1)(x+2)-6)=0

We multiply parentheses ..

x^2-((+x^2+2x-1x-2)-6)-6x=0



We calculate terms in parentheses: -((+x^2+2x-1x-2)-6), so:

(+x^2+2x-1x-2)-6

We get rid of parentheses

x^2+2x-1x-2-6

We add all the numbers together, and all the variables

x^2+x-8

Back to the equation:

-(x^2+x-8)



We add all the numbers together, and all the variables

x^2-6x-(x^2+x-8)=0

We get rid of parentheses

x^2-x^2-6x-x+8=0

We add all the numbers together, and all the variables

-7x+8=0

We move all terms containing x to the left, all other terms to the right

-7x=-8

x=-8/-7

x=1+1/7

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