3(x-19)=2(29-x)

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Solution for 3(x-19)=2(29-x) equation: 



3(x-19)=2(29-x)

We move all terms to the left:

3(x-19)-(2(29-x))=0

We add all the numbers together, and all the variables

3(x-19)-(2(-1x+29))=0

We multiply parentheses

3x-(2(-1x+29))-57=0



We calculate terms in parentheses: -(2(-1x+29)), so:

2(-1x+29)

We multiply parentheses

-2x+58

Back to the equation:

-(-2x+58)



We get rid of parentheses

3x+2x-58-57=0

We add all the numbers together, and all the variables

5x-115=0

We move all terms containing x to the left, all other terms to the right

5x=115

x=115/5

x=23

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