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x(x-36)=1525
We move all terms to the left:
x(x-36)-(1525)=0
We multiply parentheses
x^2-36x-1525=0
a = 1; b = -36; c = -1525;
Δ = b2-4ac
Δ = -362-4·1·(-1525)
Δ = 7396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7396}=86$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-86}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+86}{2*1}=\frac{122}{2} =61 $
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