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(6x+10)(5x+28)=180
We move all terms to the left:
(6x+10)(5x+28)-(180)=0
We multiply parentheses ..
(+30x^2+168x+50x+280)-180=0
We get rid of parentheses
30x^2+168x+50x+280-180=0
We add all the numbers together, and all the variables
30x^2+218x+100=0
a = 30; b = 218; c = +100;
Δ = b2-4ac
Δ = 2182-4·30·100
Δ = 35524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{35524}=\sqrt{4*8881}=\sqrt{4}*\sqrt{8881}=2\sqrt{8881}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(218)-2\sqrt{8881}}{2*30}=\frac{-218-2\sqrt{8881}}{60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(218)+2\sqrt{8881}}{2*30}=\frac{-218+2\sqrt{8881}}{60} $
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