x(x-2)-5=x(x-3)

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Solution for x(x-2)-5=x(x-3) equation: 



x(x-2)-5=x(x-3)

We move all terms to the left:

x(x-2)-5-(x(x-3))=0

We multiply parentheses

x^2-2x-(x(x-3))-5=0



We calculate terms in parentheses: -(x(x-3)), so:

x(x-3)

We multiply parentheses

x^2-3x

Back to the equation:

-(x^2-3x)



We get rid of parentheses

x^2-x^2-2x+3x-5=0

We add all the numbers together, and all the variables

x-5=0

We move all terms containing x to the left, all other terms to the right

x=5

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