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25-4(6y+5)+3y=16-11(2y+1)
We move all terms to the left:
25-4(6y+5)+3y-(16-11(2y+1))=0
We add all the numbers together, and all the variables
3y-4(6y+5)-(16-11(2y+1))+25=0
We multiply parentheses
3y-24y-(16-11(2y+1))-20+25=0
We calculate terms in parentheses: -(16-11(2y+1)), so:We add all the numbers together, and all the variables
16-11(2y+1)
determiningTheFunctionDomain -11(2y+1)+16
We multiply parentheses
-22y-11+16
We add all the numbers together, and all the variables
-22y+5
Back to the equation:
-(-22y+5)
-21y-(-22y+5)+5=0
We get rid of parentheses
-21y+22y-5+5=0
We add all the numbers together, and all the variables
y=0
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