(1)/(q+4)-(7)/(q-2)=1

Simple and best practice solution for (1)/(q+4)-(7)/(q-2)=1 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for (1)/(q+4)-(7)/(q-2)=1 equation: 



(1)/(q+4)-(7)/(q-2)=1

We move all terms to the left:

(1)/(q+4)-(7)/(q-2)-(1)=0



Domain of the equation: (q+4)!=0

We move all terms containing q to the left, all other terms to the right

q!=-4

q∈R





Domain of the equation: (q-2)!=0

We move all terms containing q to the left, all other terms to the right

q!=2

q∈R



We calculate fractions


(1*(q-2))/((q+4)*(q-2))+(-7q-28)/((q+4)*(q-2))-1=0



We calculate terms in parentheses: +(1*(q-2))/((q+4)*(q-2)), so:

1*(q-2))/((q+4)*(q-2)

We multiply all the terms by the denominator


1*(q-2))

Back to the equation:

+(1*(q-2)))





We calculate terms in parentheses: +(-7q-28)/((q+4)*(q-2)), so:

-7q-28)/((q+4)*(q-2)

We multiply all the terms by the denominator


-7q*((q+4)*(q-2)-28)

Back to the equation:

+(-7q*((q+4)*(q-2)-28))

See similar equations:

| 4t2-12t+9=0 | | 2x+15=29* | | 7/2x4=1/2+1/2x | | 2+4n=8n+6 | | -25z+11=-14 | | 3x2x=36 | | 4+6c=2(c+6) | | 3x2x=18 | | 3x2x=45 | | 2x+2=×+6 | | -9t-19=-1 | | 13+x=6x+1 | | -9t-18=-1 | | 13x+1=6x+1 | | 1/5-x/5=x/2+1/2-1 | | 72w+3=9 | | x2-3=5 | | r13=14 | | 3x+1+2x–2=64 | | |8*x-35|=10*x | | |8x-35|=10x | | 52x-9=125 | | 2x-3/2=-x-1/4 | | 3a/4-2a/3=⅚+a | | y-3-y+9=8y | | 3x2x=180 | | 6x-8x.5=41 | | 17.8=h-3.4 | | 8x−5=−8x+59 | | 7k−4k=15k= | | 7/x-13=15 | | 3+34c​ =5 |

Equations solver categories