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x(x-16)=-39
We move all terms to the left:
x(x-16)-(-39)=0
We add all the numbers together, and all the variables
x(x-16)+39=0
We multiply parentheses
x^2-16x+39=0
a = 1; b = -16; c = +39;
Δ = b2-4ac
Δ = -162-4·1·39
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-10}{2*1}=\frac{6}{2} =3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+10}{2*1}=\frac{26}{2} =13 $
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