-7(k+4)-2k=3(2k+9)+5

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Solution for -7(k+4)-2k=3(2k+9)+5 equation: 



-7(k+4)-2k=3(2k+9)+5

We move all terms to the left:

-7(k+4)-2k-(3(2k+9)+5)=0

We add all the numbers together, and all the variables

-2k-7(k+4)-(3(2k+9)+5)=0

We multiply parentheses

-2k-7k-(3(2k+9)+5)-28=0



We calculate terms in parentheses: -(3(2k+9)+5), so:

3(2k+9)+5

We multiply parentheses

6k+27+5

We add all the numbers together, and all the variables

6k+32

Back to the equation:

-(6k+32)



We add all the numbers together, and all the variables

-9k-(6k+32)-28=0

We get rid of parentheses

-9k-6k-32-28=0

We add all the numbers together, and all the variables

-15k-60=0

We move all terms containing k to the left, all other terms to the right

-15k=60

k=60/-15

k=-4

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