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x(x+78)=928
We move all terms to the left:
x(x+78)-(928)=0
We multiply parentheses
x^2+78x-928=0
a = 1; b = 78; c = -928;
Δ = b2-4ac
Δ = 782-4·1·(-928)
Δ = 9796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9796}=\sqrt{4*2449}=\sqrt{4}*\sqrt{2449}=2\sqrt{2449}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(78)-2\sqrt{2449}}{2*1}=\frac{-78-2\sqrt{2449}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(78)+2\sqrt{2449}}{2*1}=\frac{-78+2\sqrt{2449}}{2} $
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