9w-3+2(2w+1)=3(w+3)

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Solution for 9w-3+2(2w+1)=3(w+3) equation: 



9w-3+2(2w+1)=3(w+3)

We move all terms to the left:

9w-3+2(2w+1)-(3(w+3))=0

We multiply parentheses

9w+4w-(3(w+3))+2-3=0



We calculate terms in parentheses: -(3(w+3)), so:

3(w+3)

We multiply parentheses

3w+9

Back to the equation:

-(3w+9)



We add all the numbers together, and all the variables

13w-(3w+9)-1=0

We get rid of parentheses

13w-3w-9-1=0

We add all the numbers together, and all the variables

10w-10=0

We move all terms containing w to the left, all other terms to the right

10w=10

w=10/10

w=1

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