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x(x+6)=(x+11)(x-3)
We move all terms to the left:
x(x+6)-((x+11)(x-3))=0
We multiply parentheses
x^2+6x-((x+11)(x-3))=0
We multiply parentheses ..
x^2-((+x^2-3x+11x-33))+6x=0
We calculate terms in parentheses: -((+x^2-3x+11x-33)), so:We add all the numbers together, and all the variables
(+x^2-3x+11x-33)
We get rid of parentheses
x^2-3x+11x-33
We add all the numbers together, and all the variables
x^2+8x-33
Back to the equation:
-(x^2+8x-33)
x^2+6x-(x^2+8x-33)=0
We get rid of parentheses
x^2-x^2+6x-8x+33=0
We add all the numbers together, and all the variables
-2x+33=0
We move all terms containing x to the left, all other terms to the right
-2x=-33
x=-33/-2
x=16+1/2
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