(2x-1)(6+4x)=0

Solution for (2x-1)(6+4x)=0 equation:

(2x-1)(6+4x)=0

We add all the numbers together, and all the variables

(2x-1)(4x+6)=0

We multiply parentheses ..

(+8x^2+12x-4x-6)=0

We get rid of parentheses

8x^2+12x-4x-6=0

We add all the numbers together, and all the variables

8x^2+8x-6=0

a = 8; b = 8; c = -6;
Δ = b2-4ac
Δ = 82-4·8·(-6)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-16}{2*8}=\frac{-24}{16}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+16}{2*8}=\frac{8}{16}
=1/2
$