x(x+14)=1320

Solution for x(x+14)=1320 equation:

x(x+14)=1320

We move all terms to the left:

x(x+14)-(1320)=0

We multiply parentheses

x^2+14x-1320=0

a = 1; b = 14; c = -1320;
Δ = b2-4ac
Δ = 142-4·1·(-1320)
Δ = 5476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5476}=74$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-74}{2*1}=\frac{-88}{2}
=-44
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+74}{2*1}=\frac{60}{2}
=30
$