2r+3=3(-3r-5)

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Solution for 2r+3=3(-3r-5) equation: 



2r+3=3(-3r-5)

We move all terms to the left:

2r+3-(3(-3r-5))=0



We calculate terms in parentheses: -(3(-3r-5)), so:

3(-3r-5)

We multiply parentheses

-9r-15

Back to the equation:

-(-9r-15)



We get rid of parentheses

2r+9r+15+3=0

We add all the numbers together, and all the variables

11r+18=0

We move all terms containing r to the left, all other terms to the right

11r=-18

r=-18/11

r=-1+7/11

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