x(x+1)=x(x-3)+12

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Solution for x(x+1)=x(x-3)+12 equation: 



x(x+1)=x(x-3)+12

We move all terms to the left:

x(x+1)-(x(x-3)+12)=0

We multiply parentheses

x^2+x-(x(x-3)+12)=0



We calculate terms in parentheses: -(x(x-3)+12), so:

x(x-3)+12

We multiply parentheses

x^2-3x+12

Back to the equation:

-(x^2-3x+12)



We get rid of parentheses

x^2-x^2+x+3x-12=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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