5(2-m)=-3(m+2)

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Solution for 5(2-m)=-3(m+2) equation: 



5(2-m)=-3(m+2)

We move all terms to the left:

5(2-m)-(-3(m+2))=0

We add all the numbers together, and all the variables

5(-1m+2)-(-3(m+2))=0

We multiply parentheses

-5m-(-3(m+2))+10=0



We calculate terms in parentheses: -(-3(m+2)), so:

-3(m+2)

We multiply parentheses

-3m-6

Back to the equation:

-(-3m-6)



We get rid of parentheses

-5m+3m+6+10=0

We add all the numbers together, and all the variables

-2m+16=0

We move all terms containing m to the left, all other terms to the right

-2m=-16

m=-16/-2

m=+8

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