x(x+1)=9x2+3

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Solution for x(x+1)=9x2+3 equation: 



x(x+1)=9x^2+3

We move all terms to the left:

x(x+1)-(9x^2+3)=0

We multiply parentheses

x^2+x-(9x^2+3)=0

We get rid of parentheses

x^2-9x^2+x-3=0

We add all the numbers together, and all the variables

-8x^2+x-3=0

a = -8; b = 1; c = -3;
Δ = b2-4ac
Δ = 12-4·(-8)·(-3)
Δ = -95
Delta is less than zero, so there is no solution for the equation

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