6f+2(-5+3f)=1-f

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Solution for 6f+2(-5+3f)=1-f equation: 



6f+2(-5+3f)=1-f

We move all terms to the left:

6f+2(-5+3f)-(1-f)=0

We add all the numbers together, and all the variables

6f+2(3f-5)-(-1f+1)=0

We multiply parentheses

6f+6f-(-1f+1)-10=0

We get rid of parentheses

6f+6f+1f-1-10=0

We add all the numbers together, and all the variables

13f-11=0

We move all terms containing f to the left, all other terms to the right

13f=11

f=11/13

f=11/13

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