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x(x+1)=5-2x
We move all terms to the left:
x(x+1)-(5-2x)=0
We add all the numbers together, and all the variables
x(x+1)-(-2x+5)=0
We multiply parentheses
x^2+x-(-2x+5)=0
We get rid of parentheses
x^2+x+2x-5=0
We add all the numbers together, and all the variables
x^2+3x-5=0
a = 1; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·1·(-5)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{29}}{2*1}=\frac{-3-\sqrt{29}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{29}}{2*1}=\frac{-3+\sqrt{29}}{2} $
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