5(x+2)=10-3x2

Solution for 5(x+2)=10-3x2 equation:

5(x+2)=10-3x^2

We move all terms to the left:

5(x+2)-(10-3x^2)=0

We multiply parentheses

-(10-3x^2)+5x+10=0

We get rid of parentheses

3x^2+5x-10+10=0

We add all the numbers together, and all the variables

3x^2+5x=0

a = 3; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·3·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*3}=\frac{-10}{6}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*3}=\frac{0}{6}
=0
$