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x(600-12x)=0
We add all the numbers together, and all the variables
x(-12x+600)=0
We multiply parentheses
-12x^2+600x=0
a = -12; b = 600; c = 0;
Δ = b2-4ac
Δ = 6002-4·(-12)·0
Δ = 360000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{360000}=600$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(600)-600}{2*-12}=\frac{-1200}{-24} =+50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(600)+600}{2*-12}=\frac{0}{-24} =0 $
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