192=(x+4)(x)

Solution for 192=(x+4)(x) equation:

192=(x+4)(x)

We move all terms to the left:

192-((x+4)(x))=0


We calculate terms in parentheses: -((x+4)x), so:

(x+4)x

We multiply parentheses

x^2+4x

Back to the equation:

-(x^2+4x)


We get rid of parentheses

-x^2-4x+192=0

We add all the numbers together, and all the variables

-1x^2-4x+192=0

a = -1; b = -4; c = +192;
Δ = b2-4ac
Δ = -42-4·(-1)·192
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-28}{2*-1}=\frac{-24}{-2}
=+12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+28}{2*-1}=\frac{32}{-2}
=-16
$