x(3x-7)=(3x+1)(x-2)

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Solution for x(3x-7)=(3x+1)(x-2) equation: 



x(3x-7)=(3x+1)(x-2)

We move all terms to the left:

x(3x-7)-((3x+1)(x-2))=0

We multiply parentheses

3x^2-7x-((3x+1)(x-2))=0

We multiply parentheses ..

3x^2-((+3x^2-6x+x-2))-7x=0



We calculate terms in parentheses: -((+3x^2-6x+x-2)), so:

(+3x^2-6x+x-2)

We get rid of parentheses

3x^2-6x+x-2

We add all the numbers together, and all the variables

3x^2-5x-2

Back to the equation:

-(3x^2-5x-2)



We add all the numbers together, and all the variables

3x^2-7x-(3x^2-5x-2)=0

We get rid of parentheses

3x^2-3x^2-7x+5x+2=0

We add all the numbers together, and all the variables

-2x+2=0

We move all terms containing x to the left, all other terms to the right

-2x=-2

x=-2/-2

x=1

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