4(2b-5)-2b=6(b-4)-5

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Solution for 4(2b-5)-2b=6(b-4)-5 equation: 



4(2b-5)-2b=6(b-4)-5

We move all terms to the left:

4(2b-5)-2b-(6(b-4)-5)=0

We add all the numbers together, and all the variables

-2b+4(2b-5)-(6(b-4)-5)=0

We multiply parentheses

-2b+8b-(6(b-4)-5)-20=0



We calculate terms in parentheses: -(6(b-4)-5), so:

6(b-4)-5

We multiply parentheses

6b-24-5

We add all the numbers together, and all the variables

6b-29

Back to the equation:

-(6b-29)



We add all the numbers together, and all the variables

6b-(6b-29)-20=0

We get rid of parentheses

6b-6b+29-20=0

We add all the numbers together, and all the variables

9!=0

There is no solution for this equation

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