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x(3x-15)=900
We move all terms to the left:
x(3x-15)-(900)=0
We multiply parentheses
3x^2-15x-900=0
a = 3; b = -15; c = -900;
Δ = b2-4ac
Δ = -152-4·3·(-900)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11025}=105$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-105}{2*3}=\frac{-90}{6} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+105}{2*3}=\frac{120}{6} =20 $
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