(x*x)+7x+7x+49=29

Solution for (x*x)+7x+7x+49=29 equation:

(x*x)+7x+7x+49=29

We move all terms to the left:

(x*x)+7x+7x+49-(29)=0

We add all the numbers together, and all the variables

(+x*x)+7x+7x+49-29=0

We add all the numbers together, and all the variables

14x+(+x*x)+20=0

We get rid of parentheses

14x+x*x+20=0

Wy multiply elements

x^2+14x+20=0

a = 1; b = 14; c = +20;
Δ = b2-4ac
Δ = 142-4·1·20
Δ = 116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{116}=\sqrt{4*29}=\sqrt{4}*\sqrt{29}=2\sqrt{29}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{29}}{2*1}=\frac{-14-2\sqrt{29}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{29}}{2*1}=\frac{-14+2\sqrt{29}}{2}
$