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x(2x-7)=(2x+7)(x-6)
We move all terms to the left:
x(2x-7)-((2x+7)(x-6))=0
We multiply parentheses
2x^2-7x-((2x+7)(x-6))=0
We multiply parentheses ..
2x^2-((+2x^2-12x+7x-42))-7x=0
We calculate terms in parentheses: -((+2x^2-12x+7x-42)), so:We add all the numbers together, and all the variables
(+2x^2-12x+7x-42)
We get rid of parentheses
2x^2-12x+7x-42
We add all the numbers together, and all the variables
2x^2-5x-42
Back to the equation:
-(2x^2-5x-42)
2x^2-7x-(2x^2-5x-42)=0
We get rid of parentheses
2x^2-2x^2-7x+5x+42=0
We add all the numbers together, and all the variables
-2x+42=0
We move all terms containing x to the left, all other terms to the right
-2x=-42
x=-42/-2
x=+21
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