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2/3y+6=2/4(y+9)
We move all terms to the left:
2/3y+6-(2/4(y+9))=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
Domain of the equation: 4(y+9))!=0We calculate fractions
y∈R
(8yy/(12y^2y+(-(2*3y)/(12y^2y+6=0
We can not solve this equation
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