x(2x-4)=2x-12(x+5)

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Solution for x(2x-4)=2x-12(x+5) equation:



x(2x-4)=2x-12(x+5)
We move all terms to the left:
x(2x-4)-(2x-12(x+5))=0
We multiply parentheses
2x^2-4x-(2x-12(x+5))=0
We calculate terms in parentheses: -(2x-12(x+5)), so:
2x-12(x+5)
We multiply parentheses
2x-12x-60
We add all the numbers together, and all the variables
-10x-60
Back to the equation:
-(-10x-60)
We get rid of parentheses
2x^2-4x+10x+60=0
We add all the numbers together, and all the variables
2x^2+6x+60=0
a = 2; b = 6; c = +60;
Δ = b2-4ac
Δ = 62-4·2·60
Δ = -444
Delta is less than zero, so there is no solution for the equation

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