3(2x-5)=5(x-4)=5

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Solution for 3(2x-5)=5(x-4)=5 equation: 



3(2x-5)=5(x-4)=5

We move all terms to the left:

3(2x-5)-(5(x-4))=0

We multiply parentheses

6x-(5(x-4))-15=0



We calculate terms in parentheses: -(5(x-4)), so:

5(x-4)

We multiply parentheses

5x-20

Back to the equation:

-(5x-20)



We get rid of parentheses

6x-5x+20-15=0

We add all the numbers together, and all the variables

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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