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x(2x-1)=1950
We move all terms to the left:
x(2x-1)-(1950)=0
We multiply parentheses
2x^2-1x-1950=0
a = 2; b = -1; c = -1950;
Δ = b2-4ac
Δ = -12-4·2·(-1950)
Δ = 15601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{15601}}{2*2}=\frac{1-\sqrt{15601}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{15601}}{2*2}=\frac{1+\sqrt{15601}}{4} $
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