H(T)=160t-16t2

Solution for H(T)=160t-16t2 equation:

()=160H-16H^2

We move all terms to the left:

()-(160H-16H^2)=0

We add all the numbers together, and all the variables

-(160H-16H^2)=0

We get rid of parentheses

16H^2-160H=0

a = 16; b = -160; c = 0;
Δ = b2-4ac
Δ = -1602-4·16·0
Δ = 25600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25600}=160$
$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-160}{2*16}=\frac{0}{32}
=0
$
$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+160}{2*16}=\frac{320}{32}
=10
$