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x(25-x)=50
We move all terms to the left:
x(25-x)-(50)=0
We add all the numbers together, and all the variables
x(-1x+25)-50=0
We multiply parentheses
-1x^2+25x-50=0
a = -1; b = 25; c = -50;
Δ = b2-4ac
Δ = 252-4·(-1)·(-50)
Δ = 425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{425}=\sqrt{25*17}=\sqrt{25}*\sqrt{17}=5\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{17}}{2*-1}=\frac{-25-5\sqrt{17}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{17}}{2*-1}=\frac{-25+5\sqrt{17}}{-2} $
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