If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x(2)=2x-3
We move all terms to the left:
x(2)-(2x-3)=0
We add all the numbers together, and all the variables
x^2-(2x-3)=0
We get rid of parentheses
x^2-2x+3=0
a = 1; b = -2; c = +3;
Δ = b2-4ac
Δ = -22-4·1·3
Δ = -8
Delta is less than zero, so there is no solution for the equation
| {1}{2}x=8 | | x(1)=2x-3 | | 144+0=-2(x+5) | | 49=7-6(6r+6) | | x(0)=2x-3 | | -5=n-6(4n-3) | | x(-2)=2x-3 | | 9x-36=16 | | 9x-36=17 | | F(x)=x^2+7x-1 | | 9x-36=14 | | -2(2b+6)-b=8 | | 8x+12.8=-16 | | 9x-36=13 | | 9x-36=11 | | 9x-36=10 | | 6=-7(n-3)+4n | | 5^{3x}=5^{2x-7} | | 3.6/k=0.20.5 | | 1/2(6x-10)=4 | | -2=-2(7n-6) | | -28=0.41x | | .2.46=2.8/s | | 20=5(-1+k)+5 | | 55.7+u=32.119 | | 0.90d=0.89d+10 | | 2(x-1)-3(x+2)=5x+1 | | x=3(4/3) | | -5=-(3x+8) | | 23/4w=36/5 | | -7(-6r-1)=49 | | 7+10=56+6=x |