6=-7(n-3)+4n

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Solution for 6=-7(n-3)+4n equation: 



6=-7(n-3)+4n

We move all terms to the left:

6-(-7(n-3)+4n)=0



We calculate terms in parentheses: -(-7(n-3)+4n), so:

-7(n-3)+4n

We add all the numbers together, and all the variables

4n-7(n-3)

We multiply parentheses

4n-7n+21

We add all the numbers together, and all the variables

-3n+21

Back to the equation:

-(-3n+21)



We get rid of parentheses

3n-21+6=0

We add all the numbers together, and all the variables

3n-15=0

We move all terms containing n to the left, all other terms to the right

3n=15

n=15/3

n=5

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