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x(10-x)=10x+10-x
We move all terms to the left:
x(10-x)-(10x+10-x)=0
We add all the numbers together, and all the variables
x(-1x+10)-(9x+10)=0
We multiply parentheses
-1x^2+10x-(9x+10)=0
We get rid of parentheses
-1x^2+10x-9x-10=0
We add all the numbers together, and all the variables
-1x^2+x-10=0
a = -1; b = 1; c = -10;
Δ = b2-4ac
Δ = 12-4·(-1)·(-10)
Δ = -39
Delta is less than zero, so there is no solution for the equation
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