2y+15=3(y-4)

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Solution for 2y+15=3(y-4) equation:



2y+15=3(y-4)
We move all terms to the left:
2y+15-(3(y-4))=0
We calculate terms in parentheses: -(3(y-4)), so:
3(y-4)
We multiply parentheses
3y-12
Back to the equation:
-(3y-12)
We get rid of parentheses
2y-3y+12+15=0
We add all the numbers together, and all the variables
-1y+27=0
We move all terms containing y to the left, all other terms to the right
-y=-27
y=-27/-1
y=+27

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