x^2-16x=260

Solution for x^2-16x=260 equation:

x^2-16x=260

We move all terms to the left:

x^2-16x-(260)=0

a = 1; b = -16; c = -260;
Δ = b2-4ac
Δ = -162-4·1·(-260)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-36}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+36}{2*1}=\frac{52}{2}
=26
$